0=40+2t+4.9t^2

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Solution for 0=40+2t+4.9t^2 equation: 



0=40+2t+4.9t^2

We move all terms to the left:

0-(40+2t+4.9t^2)=0

We add all the numbers together, and all the variables

-(40+2t+4.9t^2)=0

We get rid of parentheses

-4.9t^2-2t-40=0

a = -4.9; b = -2; c = -40;
Δ = b2-4ac
Δ = -22-4·(-4.9)·(-40)
Δ = -780
Delta is less than zero, so there is no solution for the equation

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